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Determine the tangential and centripetal components of the net force exerted on the car (by the ground) in Example 5–8 when its speed is 15 m/s. The car’s mass is 950 kg.

Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014. Reprinted by permission of Pearson Education Inc., New York.
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Quick Answer: 

$F_{tan} = 3.0\times 10^3\textrm{ N, } F_R = 430\textrm{ N}$

Giancoli 7th Edition, Chapter 5, Problem 24


Chapter 5, Problem 24 is solved.

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Transcript for this Giancoli solution

This is Giancoli Answers with Mr. Dychko. From the example in the textbook, we are given the tangental component of a car's acceleration and the radial component and to find the forces then in each of those directions, we multiply those accelerations by mass because these are the only forces that are involved in these directions so that makes them equal to the net force which is always given by mass times acceleration. So the tangental component of the force is mass times the tangental acceleration— 950 kilograms times 3.2 meters per second squared which gives 3.0 times 10 to the 3 newtons and I wrote it in scientific notation to show that there are two significant figures there. And the radial component of acceleration, or centripetal is another way to say it, is mass times—950 kilograms—times 0.45 meters per second squared which gives 430 newtons.