Question:

A hypothetical planet has a radius 2.0 times that of Earth, but has the same mass. What is the acceleration due to gravity near its surface?

Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014. Reprinted by permission of Pearson Education Inc., New York.

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Quick Answer:

$2.5\textrm{ m/s}^2$

### Transcript for this Giancoli solution

This is Giancoli Answers with Mr. Dychko. The acceleration due to gravity on any planet is the gravitational constant, capital*G*times the mass of the planet divided by the radius of the planet squared. We are told that the radius of this hypothetical planet is two times the radius of Earth. So we will substitute 2

*r E*in place of

*r P*and copy everything else from this formula. And, we will square that

*2 r E*on the bottom and we get four times

*r E squared*and this business here,

*G m P*over

*r E squared*is the acceleration due to gravity on Earth—

*g subscript E*. So we have one-quarter

*g*on Earth is going to be the acceleration due to gravity on this planet. That's going to be one-quarter of 9.8, which is 2.5 meters per second squared; acceleration due to gravity on this other planet.