Question:

Find the tension in the two cords shown in Fig. 9–52. Neglect the mass of the cords, and assume that the angle is $\theta$ is $33 ^\circ$ and the mass $m$ is 190 kg.

Problem 9-52.

Source: Giancoli, Douglas C., Physics: Principles with Applications, 7th Edition, 2014.

Quick Answer:

$F_1 = 3400 \textrm{ N, } F_2 = 3400 \textrm{ N}$

## Comments

Hello. There is a mistake in the snippet answer. F2 should be, indeed, 2900N.

Moreover, I wanted to know why you decided to take equation 2 and divide it by equation 1? If I am not mistaken, you already all have all of the information that you need to find F1 with equation 2, given that theta=33, mass m=190kg. All you would need to find F2 is to plug in F1 into equation 1. Just a thought...

Thank you for your helpful videos!

I agree that it doesn't make sense to do the whole equation division. That ended up confusing me and ended up solving as shown in the book instead.