The femur bone in the human leg has a minimum effective cross section of about 3.0 cm ^2 \; (= 3.0 x 10^{-4} m ^2). How much compressive force can it withstand before breaking?

This is Giancoli Answers with Mr. Dychko. The maximum compressive stress that bone can withstand is 170 times 10 to the 6 newtons per square meter which we get from table [9-2] on page 245 and that equals force over area because stress is force divided by cross-sectional area. So we multiply both sides by A and then we get F is A times that compressive strength. And so area is 3.0 times 10 to the minus 4 square meters times 170 times 10 to the 6 newtons per square meter and you get 5.1 times 10 to the 4 newtons.

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The femur bone in the human leg has a minimum effective cross section of about 3.0 cm2 (=3.0×10−4 m2)3.0 \textrm{ cm}^2 \; (= 3.0 \times 10^{-4} \textrm{ m}^2)3.0 cm2(=3.0×10−4 m2). How much compressive force can it withstand before breaking?

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The femur bone in the human leg has a minimum effective cross section of about $3.0 \textrm{ cm}^2 \; (= 3.0 \times 10^{-4} \textrm{ m}^2)$ . How much compressive force can it withstand before breaking?