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At depths of 2000 m in the sea, the pressure is about 200 times atmospheric pressure $(1 \textrm{ atm} = 1.0 \times 10^5 \textrm{ N/m}^2)$. By what percentage does the interior space of an iron bathysphere’s volume change at this depth?

Source: Giancoli, Douglas C., Physics: Principles with Applications, 7th Edition, 2014.

Quick Answer: 

$-2 \times 10^{-2} \%$

Note: The last step in the video incorrectly shows dividing by 100 when it should show multiplying by 100 to get the percentage. Thank you jsh2672 for spotting that mistake. The quick answer above is correct, whereas the video shows a mistaken result.

Giancoli 7th Edition, Chapter 9, Problem 48


Chapter 9, Problem 48 is solved.

View sample solution


Why are you multiplying by 1/100? Shouldn't you be multiplying by 100 to get the percentage?

Thank you very much jsh2672 for noticing that! I've corrected the quick answer to show the result after multiplying by 100, and put a note about the error in the video.

Best wishes,
Mr. Dychko